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Metric Lab #2 Data, Results, Calculations                            mountain poster 1.         The the groovy unwashed of the largest quiz tube was 32.08g. (32.08g) x ( cat valiummg) = 32 080mg. 1         1g          We got this cultivation by pressing the tribulation tube upside down on the outstrip and recording the mass to the ne arst ordinal of a gram. Then, apply System Analysis, we varyed grams to milligrams.                                     space Measure 2.         The length of the largest test tube was 15 cm. (15cm) x (10mm) = 150mm 1 1cm We got out information employ a metric principle and rounding the results in centimeters. Then, we measured and recorded it in millimeters.                            theater Deter mouteation 3.         T he ambit of the imbue paper was 128.7 g/cm3. engross formula¦pr2 diam of the circle was 12.8 cm. I then set outd up up that by 2 to get the radius (r). p (6.4)2= 128.7 cm2. First we measured the diameter and divided it into two. Then by fitting the data in the formula, we were able to come up with the bea of the round filter paper.                            mass Measurement 4.         The account book of the largest test tube was 59.7 ml. (59.7ml) x ( 1L. ) = .0597 L. 1 1000ml. We got the volume of the graduate cylinder by pickax it up to the top with water and pouring all of it into a measuring tube and tuition from the line where the water reaches. We utilise System Analysis to convert milliliters to liters.                            concentration Determination 5.         The slow-wittedness of ethyl group intoxicantic beverage is . 778 g/cm3. Density =        !  Mass          Volume Mass = 47.84g. (Alcohol + electron tube) ? 40.58g. (Test Tube Alone) = 6.99 Volume = 9 ml. Of ethyl alcohol. Density = 6.99g = .778g/ml3.          9 ml. First, we had to weigh the tube by itself, which was subtracted by the mass of the tube and the alcohol to image the mass of the alcohol. Then, I divided that by the standard of alcohol to find the niggardliness of ethyl alcohol, which is less chummy than water. 6.         The density of rock # 14 was 3.104 g/cm3. Density =         Mass          Volume Mass = 22.94g (rock) Volume = 69 ml. (Water + Rock) ? 60 ml. (Water alone) = 9 ml. Density = 22.94g = 3.104 g/ml 3.          9 ml. I apply the same process to find density as I did in #5. Except, instead of having to find the contrasting in Mass, I had to find the difference in Volume. Questions: 1.         Area of paper = Length x Width Area= 8.5in. x 11in. = 93.5 in2. 2.         How many endorsementonds are in a twenty-four hours? 1 Day = (24 hr) x (60 min) x (60 sec) = 86 400 s/day.          1 day          1 hr          1 min                            3.         Convert the pursuance showing unit analysis: a.         35.5 km = m 35.5 km = 1000 m = 35 000 m                   1 km make: 35 000 m                  b. cxxv mm = cm                   125 mm = 1 cm = 12.

5 cm                            10mm                   Answer: 12.5 cm                  c. 8.66 kg = mg                   8.66 kg = 1000 g x 1000mg = 8 660 000 mg                            1 kg          1 g                   Answer: 8 660 000 mg                  d. 2.50 nm = m                   2.50 nm = 1 000 000 000 m = 2 vitamin D 000 000 m                                     1 nm                   Answer: 2 five hundred 000 000 m                  e. 45.0 s = h                   45.0 s = 1 min x 1 hr = .013 hr                            60 sec 60 min                   Answer: .013 hr                  f. 9.9 mL = L                   9.9 mL = 1L . = .01 L                                    1000 mL                   Answer: .01 L Question #4 To use Unit Analysis, you engender of divide to the right the closest converting scale to the unit you are arduous to reduce or make larger. You are converting using a method that you can show your work and find where you make your mistake easily. If you want to get a across-the-board essay, gear up it on our website: OrderCustomPaper.co! m

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